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1820-54x-4.9x^2=0
a = -4.9; b = -54; c = +1820;
Δ = b2-4ac
Δ = -542-4·(-4.9)·1820
Δ = 38588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{38588}=\sqrt{4*9647}=\sqrt{4}*\sqrt{9647}=2\sqrt{9647}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-2\sqrt{9647}}{2*-4.9}=\frac{54-2\sqrt{9647}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+2\sqrt{9647}}{2*-4.9}=\frac{54+2\sqrt{9647}}{-9.8} $
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